Digital input and Analog input

For this week’s assignment, we are asked to use at least one analog input to control one LED and at least one digital input to control one LED. I haven’t added the sketch yet so I am going to come back and add that creative element later!

I had fun with the line graph displaying the knobValue before and after being mapped. I made the graph curve by rotating the potentiometer. Below are the graph and the video of that:

Testing the button (digital input) and the potentiometer (analog input):


This is the code (how to make it color-coded though?) (updated: oh! it is color-coded in the post but not right in the editing space)

const int ledPinYellow = 3;
const int ledPinGreen = 7;
const int ledPinBlue = 12;
const int buttonPin = 2; 
int knobPin = A0;
int ledState = LOW;
int prevButtonState = LOW;

void setup() {
  pinMode(ledPinYellow, OUTPUT);
  pinMode(ledPinGreen, OUTPUT);
  pinMode(ledPinBlue, OUTPUT);
  pinMode(buttonPin, INPUT);
  //pinMode(A0, INPUT);


void loop() {
  int knobValue = analogRead(knobPin);
  int mappedValue = map(knobValue, 0, 1023, 0, 255);
  Serial.print("    ");

  analogWrite(ledPinYellow, mappedValue);

  int currentButtonState = digitalRead(buttonPin);
  if (currentButtonState == HIGH && prevButtonState == LOW) {
      // flip the LED state
      if (ledState == HIGH){
        ledState = LOW;
      } else if (ledState == LOW){
        ledState = HIGH;
  // if you want to print out the LED state
  // Serial.print(ledState);
  digitalWrite(ledPinGreen, ledState);
  digitalWrite(ledPinBlue, !ledState);
  //we need to remember the state of our button for the next time through LOOP
  prevButtonState = currentButtonState;


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